BPSC TRE-2: Bihar Public Service Commission has announced the second phase teacher recruitment process with some changes and amendments in the Bihar Teacher Recruitment Examination Pattern. The application process for second phase teacher recruitment-2 will start from tomorrow, Sunday, 5th November 2023. Registration for teacher recruitment will start from 5th November and applications will start from 10th November. BPSC Chairman Atul Prasad held a press conference in this regard today and informed about the important changes in the BPSC exam. Commission Chairman said that keeping in mind the problems faced by the candidates in the process of TI-1, some changes have been made in some teacher recruitment examinations.
The online application process for TRE-2 will start from 5th November 2023. The last date for registration and payment of application fees for teacher recruitment will be 14 November 2023. The last date for filling online application is 25 November 2023. The Commission said that the vacancies arising due to candidates not completing the document verification during appointment after the Teacher Recruitment (TRE-1) examination, will be filled through the supplementary result only. Regarding the high number of vacancies in secondary schools in the ongoing recruitment process of teachers, he said that STET examination was not conducted since 2019, due to which some applications came less and vacancies remained high.
Know 8 important things including BPSC TI-2 exam pattern-
1- Teacher recruitment examination was earlier being held for two days which will now be held in one day. With this, candidates will not have to take unnecessary night halt.
2- Now there will be a total of 50 questions in the question paper, out of which a total of 30 questions will be of qualifying nature.
3- Even though there is a tie breaker in merit, some changes have been made. In TRE-1, names were taken on date of birth and alphabetical order in tie breaker. The tie breaker will be decided on the basis of performance in Part 3 of the paper.
4- By combining Part 2 and Part 3 of the paper, there will be a total of 120 marks for the merit list. If there is a tie breaker result then the eligible candidate will be selected on the basis of marks of Part-3. If there is a tie breaker in Part 3 also, then the one who gets more marks in Language, which is of qualifying nature, will be considered qualified.
5- There will be a tiebreaker in the language subject also, then after this name and date of birth will be given preference.
6- In the language part of the paper (30 questions), 8 questions will be of English language and 22 questions will be of Hindi. The language section will be of total 30 marks out of which 9 marks will be considered qualifying.
7- In the main paper Part-1 and Part-2, question setting ratio will be 40 and 80 i.e. total 120 marks. There will be 40 marks for General Studies and 80 marks for related subjects. The cutoff syllabus in this paper will remain the same as TRE-1. No changes were made in its curriculum. Questions in the course will be from NCERT syllabus but the standard of the exam will be above the syllabus. That means, for graduate level posts, there will be graduate level curriculum and for PG level posts, there will be PG level curriculum.
8 – An attempt will be made to add TRE-1 vacancies also in this recruitment. In this recruitment, there will be 16140 posts for class 6 to 8 and a total of 18877 posts for class 9 to 10. Apart from this, there are 18577 vacancies for higher secondary category (class 11 and 12).
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